Base | Representation |
---|---|
bin | 11110010001010011000000… |
… | …010001111011101110111011 |
3 | 122110101002212211212102202111 |
4 | 132101103000101323232323 |
5 | 114422200301222432103 |
6 | 1151051031551313151 |
7 | 40020220206543052 |
oct | 3621230021735673 |
9 | 573332784772674 |
10 | 133130032233403 |
11 | 39468147559507 |
12 | 12b215aa51b7b7 |
13 | 593915386431a |
14 | 24c3756951399 |
15 | 105d03e8bb86d |
hex | 7914c047bbbb |
133130032233403 has 2 divisors, whose sum is σ = 133130032233404. Its totient is φ = 133130032233402.
The previous prime is 133130032233329. The next prime is 133130032233409. The reversal of 133130032233403 is 304332230031331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133130032233403 - 241 = 130931008977851 is a prime.
It is not a weakly prime, because it can be changed into another prime (133130032233409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66565016116701 + 66565016116702.
It is an arithmetic number, because the mean of its divisors is an integer number (66565016116702).
Almost surely, 2133130032233403 is an apocalyptic number.
133130032233403 is a deficient number, since it is larger than the sum of its proper divisors (1).
133130032233403 is an equidigital number, since it uses as much as digits as its factorization.
133130032233403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 31.
Adding to 133130032233403 its reverse (304332230031331), we get a palindrome (437462262264734).
The spelling of 133130032233403 in words is "one hundred thirty-three trillion, one hundred thirty billion, thirty-two million, two hundred thirty-three thousand, four hundred three".
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