Base | Representation |
---|---|
bin | 11110010001010011000000… |
… | …010001111011111001001001 |
3 | 122110101002212211212110122201 |
4 | 132101103000101323321021 |
5 | 114422200301222442212 |
6 | 1151051031551320201 |
7 | 40020220206545005 |
oct | 3621230021737111 |
9 | 573332784773581 |
10 | 133130032234057 |
11 | 39468147559a51 |
12 | 12b215aa520061 |
13 | 5939153864701 |
14 | 24c3756951705 |
15 | 105d03e8bbb57 |
hex | 7914c047be49 |
133130032234057 has 2 divisors, whose sum is σ = 133130032234058. Its totient is φ = 133130032234056.
The previous prime is 133130032234037. The next prime is 133130032234103. The reversal of 133130032234057 is 750432230031331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84571768156681 + 48558264077376 = 9196291^2 + 6968376^2 .
It is a cyclic number.
It is not a de Polignac number, because 133130032234057 - 223 = 133130023845449 is a prime.
It is not a weakly prime, because it can be changed into another prime (133130032234037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66565016117028 + 66565016117029.
It is an arithmetic number, because the mean of its divisors is an integer number (66565016117029).
Almost surely, 2133130032234057 is an apocalyptic number.
It is an amenable number.
133130032234057 is a deficient number, since it is larger than the sum of its proper divisors (1).
133130032234057 is an equidigital number, since it uses as much as digits as its factorization.
133130032234057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 37.
Adding to 133130032234057 its reverse (750432230031331), we get a palindrome (883562262265388).
The spelling of 133130032234057 in words is "one hundred thirty-three trillion, one hundred thirty billion, thirty-two million, two hundred thirty-four thousand, fifty-seven".
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