Base | Representation |
---|---|
bin | 11110010001010100110110… |
… | …100010011001011110111011 |
3 | 122110101022000010011111000222 |
4 | 132101110312202121132323 |
5 | 114422213332130323201 |
6 | 1151052000504050255 |
7 | 40020320320522163 |
oct | 3621246642313673 |
9 | 573338003144028 |
10 | 133132016261051 |
11 | 39468a75486885 |
12 | 12b21a62a6398b |
13 | 59393ab908592 |
14 | 24c38a424d5a3 |
15 | 105d108b7691b |
hex | 7915368997bb |
133132016261051 has 2 divisors, whose sum is σ = 133132016261052. Its totient is φ = 133132016261050.
The previous prime is 133132016261029. The next prime is 133132016261063. The reversal of 133132016261051 is 150162610231331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133132016261051 - 218 = 133132015998907 is a prime.
It is not a weakly prime, because it can be changed into another prime (133132016261081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66566008130525 + 66566008130526.
It is an arithmetic number, because the mean of its divisors is an integer number (66566008130526).
Almost surely, 2133132016261051 is an apocalyptic number.
133132016261051 is a deficient number, since it is larger than the sum of its proper divisors (1).
133132016261051 is an equidigital number, since it uses as much as digits as its factorization.
133132016261051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 35.
Adding to 133132016261051 its reverse (150162610231331), we get a palindrome (283294626492382).
The spelling of 133132016261051 in words is "one hundred thirty-three trillion, one hundred thirty-two billion, sixteen million, two hundred sixty-one thousand, fifty-one".
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