Base | Representation |
---|---|
bin | 1100000110111011100010… |
… | …1100011101011100110011 |
3 | 1202010201200221220112202120 |
4 | 3001232320230131130303 |
5 | 3221110414243004021 |
6 | 44152000053045323 |
7 | 2542563364341366 |
oct | 301567054353463 |
9 | 52121627815676 |
10 | 13313202313011 |
11 | 42731086a4187 |
12 | 15b0230626843 |
13 | 757577a72a53 |
14 | 3405107180dd |
15 | 181490e0c2c6 |
hex | c1bb8b1d733 |
13313202313011 has 4 divisors (see below), whose sum is σ = 17750936417352. Its totient is φ = 8875468208672.
The previous prime is 13313202312967. The next prime is 13313202313051. The reversal of 13313202313011 is 11031320231331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13313202313011 - 213 = 13313202304819 is a prime.
It is a super-2 number, since 2×133132023130112 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13313202313051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218867052166 + ... + 2218867052171.
It is an arithmetic number, because the mean of its divisors is an integer number (4437734104338).
Almost surely, 213313202313011 is an apocalyptic number.
13313202313011 is a deficient number, since it is larger than the sum of its proper divisors (4437734104341).
13313202313011 is an equidigital number, since it uses as much as digits as its factorization.
13313202313011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4437734104340.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 13313202313011 its reverse (11031320231331), we get a palindrome (24344522544342).
The spelling of 13313202313011 in words is "thirteen trillion, three hundred thirteen billion, two hundred two million, three hundred thirteen thousand, eleven".
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