Base | Representation |
---|---|
bin | 1100000110111011100100… |
… | …1110110010100000000110 |
3 | 1202010201201120211202020102 |
4 | 3001232321032302200012 |
5 | 3221110424043442014 |
6 | 44152001014004102 |
7 | 2542563534002036 |
oct | 301567116624006 |
9 | 52121646752212 |
10 | 13313211312134 |
11 | 4273112790378 |
12 | 15b0233646632 |
13 | 7575798a3b86 |
14 | 3405119bb8c6 |
15 | 181491ad88de |
hex | c1bb93b2806 |
13313211312134 has 4 divisors (see below), whose sum is σ = 19969816968204. Its totient is φ = 6656605656066.
The previous prime is 13313211312131. The next prime is 13313211312169. The reversal of 13313211312134 is 43121311231331.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13313211312097 and 13313211312106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13313211312131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3328302828032 + ... + 3328302828035.
It is an arithmetic number, because the mean of its divisors is an integer number (4992454242051).
Almost surely, 213313211312134 is an apocalyptic number.
13313211312134 is a deficient number, since it is larger than the sum of its proper divisors (6656605656070).
13313211312134 is an equidigital number, since it uses as much as digits as its factorization.
13313211312134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6656605656069.
The product of its digits is 3888, while the sum is 29.
Adding to 13313211312134 its reverse (43121311231331), we get a palindrome (56434522543465).
The spelling of 13313211312134 in words is "thirteen trillion, three hundred thirteen billion, two hundred eleven million, three hundred twelve thousand, one hundred thirty-four".
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