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133133314303 = 1112103028573
BaseRepresentation
bin111101111111101011…
…1010010100011111111
3110201122021211002210201
41323333113102203333
54140124112024203
6141054404544331
712422111333323
oct1737727224377
9421567732721
10133133314303
1151509315590
12219760b20a7
13c729095272
14662d695983
1536e2e8ce1d
hex1eff5d28ff

133133314303 has 4 divisors (see below), whose sum is σ = 145236342888. Its totient is φ = 121030285720.

The previous prime is 133133314283. The next prime is 133133314309. The reversal of 133133314303 is 303413331331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133133314303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133133314309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6051514276 + ... + 6051514297.

It is an arithmetic number, because the mean of its divisors is an integer number (36309085722).

Almost surely, 2133133314303 is an apocalyptic number.

133133314303 is a deficient number, since it is larger than the sum of its proper divisors (12103028585).

133133314303 is a wasteful number, since it uses less digits than its factorization.

133133314303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12103028584.

The product of its (nonzero) digits is 8748, while the sum is 28.

Adding to 133133314303 its reverse (303413331331), we get a palindrome (436546645634).

The spelling of 133133314303 in words is "one hundred thirty-three billion, one hundred thirty-three million, three hundred fourteen thousand, three hundred three".

Divisors: 1 11 12103028573 133133314303