Base | Representation |
---|---|
bin | 1100000110111110100000… |
… | …1111100011010101110011 |
3 | 1202010210202112222100021220 |
4 | 3001233220033203111303 |
5 | 3221114033002310311 |
6 | 44152211151120123 |
7 | 2542622222044053 |
oct | 301575017432563 |
9 | 52123675870256 |
10 | 13314000041331 |
11 | 4273487a23290 |
12 | 15b0413813043 |
13 | 75767410b942 |
14 | 340588651563 |
15 | 1814dae86206 |
hex | c1be83e3573 |
13314000041331 has 32 divisors (see below), whose sum is σ = 19990948724736. Its totient is φ = 7808631012000.
The previous prime is 13314000041327. The next prime is 13314000041411.
13314000041331 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 13314000041331 - 22 = 13314000041327 is a prime.
It is a super-2 number, since 2×133140000413312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13314000041311) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60934380 + ... + 61152486.
It is an arithmetic number, because the mean of its divisors is an integer number (624717147648).
Almost surely, 213314000041331 is an apocalyptic number.
13314000041331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13314000041331 is a deficient number, since it is larger than the sum of its proper divisors (6676948683405).
13314000041331 is a wasteful number, since it uses less digits than its factorization.
13314000041331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 277823.
The product of its (nonzero) digits is 1296, while the sum is 24.
It can be divided in two parts, 133140000 and 41331, that added together give a palindrome (133181331).
The spelling of 13314000041331 in words is "thirteen trillion, three hundred fourteen billion, forty-one thousand, three hundred thirty-one".
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