1331400025105 has 4 divisors (see below), whose sum is σ = 1597680030132. Its totient is φ = 1065120020080.

The previous prime is 1331400025079. The next prime is 1331400025147. The reversal of 1331400025105 is 5015200041331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 209808886401 + 1121591138704 = 458049^2 + 1059052^2 .

It is not a de Polignac number, because 1331400025105 - 2⁵ = 1331400025073 is a prime.

It is a super-2 number, since 2×1331400025105² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1331400025105.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133140002506 + ... + 133140002515.

It is an arithmetic number, because the mean of its divisors is an integer number (399420007533).

Almost surely, 2^{1331400025105} is an apocalyptic number.

It is an amenable number.

1331400025105 is a deficient number, since it is larger than the sum of its proper divisors (266280005027).

1331400025105 is an equidigital number, since it uses as much as digits as its factorization.

1331400025105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 266280005026.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 1331400025105 its reverse (5015200041331), we get a palindrome (6346600066436).

The spelling of 1331400025105 in words is "one trillion, three hundred thirty-one billion, four hundred million, twenty-five thousand, one hundred five".