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1331414102543 = 7190202014649
BaseRepresentation
bin10011010111111110011…
…101101111001000001111
311201021121112112012121112
4103113332131233020033
5133303214002240133
62455350532522235
7165122453100230
oct23277635571017
94637545465545
101331414102543
11473716607408
12196053a8037b
1398723437cb5
1448625737087
1524976c7c648
hex135fe76f20f

1331414102543 has 4 divisors (see below), whose sum is σ = 1521616117200. Its totient is φ = 1141212087888.

The previous prime is 1331414102533. The next prime is 1331414102587. The reversal of 1331414102543 is 3452014141331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1331414102543 - 28 = 1331414102287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331414102533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95101007318 + ... + 95101007331.

It is an arithmetic number, because the mean of its divisors is an integer number (380404029300).

Almost surely, 21331414102543 is an apocalyptic number.

1331414102543 is a deficient number, since it is larger than the sum of its proper divisors (190202014657).

1331414102543 is an equidigital number, since it uses as much as digits as its factorization.

1331414102543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190202014656.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1331414102543 its reverse (3452014141331), we get a palindrome (4783428243874).

The spelling of 1331414102543 in words is "one trillion, three hundred thirty-one billion, four hundred fourteen million, one hundred two thousand, five hundred forty-three".

Divisors: 1 7 190202014649 1331414102543