Base | Representation |
---|---|
bin | 10011010111111110111… |
… | …000001111110110101111 |
3 | 11201021122000121021221020 |
4 | 103113332320033312233 |
5 | 133303222242133320 |
6 | 2455351341505223 |
7 | 165122566134063 |
oct | 23277670176657 |
9 | 4637560537836 |
10 | 1331421052335 |
11 | 47371a523940 |
12 | 196056272213 |
13 | 987249cc3ba |
14 | 48626625aa3 |
15 | 249776a1940 |
hex | 135fee0fdaf |
1331421052335 has 64 divisors (see below), whose sum is σ = 2380665821184. Its totient is φ = 629959017600.
The previous prime is 1331421052321. The next prime is 1331421052411. The reversal of 1331421052335 is 5332501241331.
It is not a de Polignac number, because 1331421052335 - 24 = 1331421052319 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 1331421052296 and 1331421052305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 620100 + ... + 1745670.
It is an arithmetic number, because the mean of its divisors is an integer number (37197903456).
Almost surely, 21331421052335 is an apocalyptic number.
1331421052335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1331421052335 is a deficient number, since it is larger than the sum of its proper divisors (1049244768849).
1331421052335 is a wasteful number, since it uses less digits than its factorization.
1331421052335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1125764.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1331421052335 its reverse (5332501241331), we get a palindrome (6663922293666).
The spelling of 1331421052335 in words is "one trillion, three hundred thirty-one billion, four hundred twenty-one million, fifty-two thousand, three hundred thirty-five".
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