Base | Representation |
---|---|
bin | 10011010111111111100… |
… | …010100011111000011110 |
3 | 11201021122210110211101222 |
4 | 103113333202203320132 |
5 | 133303233112110124 |
6 | 2455352415333342 |
7 | 165123062332361 |
oct | 23277742437036 |
9 | 4637583424358 |
10 | 1331432144414 |
11 | 47372580a549 |
12 | 196059b21252 |
13 | 987270b4068 |
14 | 48627cb20d8 |
15 | 2497864325e |
hex | 135ff8a3e1e |
1331432144414 has 4 divisors (see below), whose sum is σ = 1997148216624. Its totient is φ = 665716072206.
The previous prime is 1331432144389. The next prime is 1331432144447. The reversal of 1331432144414 is 4144412341331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332858036102 + ... + 332858036105.
It is an arithmetic number, because the mean of its divisors is an integer number (499287054156).
Almost surely, 21331432144414 is an apocalyptic number.
1331432144414 is a deficient number, since it is larger than the sum of its proper divisors (665716072210).
1331432144414 is an equidigital number, since it uses as much as digits as its factorization.
1331432144414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665716072209.
The product of its digits is 55296, while the sum is 35.
Adding to 1331432144414 its reverse (4144412341331), we get a palindrome (5475844485745).
The spelling of 1331432144414 in words is "one trillion, three hundred thirty-one billion, four hundred thirty-two million, one hundred forty-four thousand, four hundred fourteen".
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