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1331450314303 = 1996690705097
BaseRepresentation
bin10011011000000000100…
…111110111111000111111
311201021201001122221210211
4103120000213313320333
5133303302240024203
62455354305013251
7165123402636664
oct23300047677077
94637631587724
101331450314303
11473734a9a88a
12196064024227
139872aaa6485
144862a481a6b
152497a031c6d
hex136009f7e3f

1331450314303 has 4 divisors (see below), whose sum is σ = 1338141019600. Its totient is φ = 1324759609008.

The previous prime is 1331450314283. The next prime is 1331450314307. The reversal of 1331450314303 is 3034130541331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1331450314303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331450314307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3345352350 + ... + 3345352747.

It is an arithmetic number, because the mean of its divisors is an integer number (334535254900).

Almost surely, 21331450314303 is an apocalyptic number.

1331450314303 is a deficient number, since it is larger than the sum of its proper divisors (6690705297).

1331450314303 is an equidigital number, since it uses as much as digits as its factorization.

1331450314303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6690705296.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 1331450314303 its reverse (3034130541331), we get a palindrome (4365580855634).

The spelling of 1331450314303 in words is "one trillion, three hundred thirty-one billion, four hundred fifty million, three hundred fourteen thousand, three hundred three".

Divisors: 1 199 6690705097 1331450314303