Base | Representation |
---|---|
bin | 11000110011010010… |
… | …01111011101111111 |
3 | 1021100221210101010212 |
4 | 30121221033131333 |
5 | 204232134043201 |
6 | 10041125423035 |
7 | 650650565333 |
oct | 143151173577 |
9 | 37327711125 |
10 | 13315143551 |
11 | 5713062476 |
12 | 26b726aa7b |
13 | 1342772588 |
14 | 9045617c3 |
15 | 52de52abb |
hex | 319a4f77f |
13315143551 has 4 divisors (see below), whose sum is σ = 14015940600. Its totient is φ = 12614346504.
The previous prime is 13315143503. The next prime is 13315143557. The reversal of 13315143551 is 15534151331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15534151331 = 449 ⋅34597219.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13315143551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13315143557) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350398496 + ... + 350398533.
It is an arithmetic number, because the mean of its divisors is an integer number (3503985150).
Almost surely, 213315143551 is an apocalyptic number.
13315143551 is a deficient number, since it is larger than the sum of its proper divisors (700797049).
13315143551 is an equidigital number, since it uses as much as digits as its factorization.
13315143551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 700797048.
The product of its digits is 13500, while the sum is 32.
Adding to 13315143551 its reverse (15534151331), we get a palindrome (28849294882).
The spelling of 13315143551 in words is "thirteen billion, three hundred fifteen million, one hundred forty-three thousand, five hundred fifty-one".
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