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133154302135 = 5194549308117
BaseRepresentation
bin111110000000010011…
…1010110100010110111
3110201200202022101200211
41330000213112202313
54140200000132020
6141100434450251
712422454615331
oct1740047264267
9421622271624
10133154302135
115151a14aaa8
1221981133987
13c7305331ba
14663239a451
1536e4c3685a
hex1f009d68b7

133154302135 has 16 divisors (see below), whose sum is σ = 168232428000. Its totient is φ = 100894432896.

The previous prime is 133154302129. The next prime is 133154302163. The reversal of 133154302135 is 531203451331.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 133154302135 - 27 = 133154302007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133154302097 and 133154302106.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 278097 + ... + 586213.

It is an arithmetic number, because the mean of its divisors is an integer number (10514526750).

Almost surely, 2133154302135 is an apocalyptic number.

133154302135 is a deficient number, since it is larger than the sum of its proper divisors (35078125865).

133154302135 is a wasteful number, since it uses less digits than its factorization.

133154302135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312690.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 133154302135 its reverse (531203451331), we get a palindrome (664357753466).

The spelling of 133154302135 in words is "one hundred thirty-three billion, one hundred fifty-four million, three hundred two thousand, one hundred thirty-five".

Divisors: 1 5 19 95 4549 22745 86431 308117 432155 1540585 5854223 29271115 1401624233 7008121165 26630860427 133154302135