Base | Representation |
---|---|
bin | 11110010001110011111101… |
… | …111100010111011110110111 |
3 | 122110111111020112102202112210 |
4 | 132101303331330113132313 |
5 | 114423240243141140110 |
6 | 1151115204041344503 |
7 | 40022612260104135 |
oct | 3621637574273667 |
9 | 573444215382483 |
10 | 133165426505655 |
11 | 3948115a713085 |
12 | 12b28427a98133 |
13 | 593c5a467249b |
14 | 24c5353570755 |
15 | 105de11d7d520 |
hex | 791cfdf177b7 |
133165426505655 has 32 divisors (see below), whose sum is σ = 215987461401600. Its totient is φ = 70047337939200.
The previous prime is 133165426505623. The next prime is 133165426505677. The reversal of 133165426505655 is 556505624561331.
It is not a de Polignac number, because 133165426505655 - 25 = 133165426505623 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133165426505595 and 133165426505604.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 58172446 + ... + 60418244.
It is an arithmetic number, because the mean of its divisors is an integer number (6749608168800).
Almost surely, 2133165426505655 is an apocalyptic number.
133165426505655 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
133165426505655 is a deficient number, since it is larger than the sum of its proper divisors (82822034895945).
133165426505655 is a wasteful number, since it uses less digits than its factorization.
133165426505655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2300031.
The product of its (nonzero) digits is 48600000, while the sum is 57.
The spelling of 133165426505655 in words is "one hundred thirty-three trillion, one hundred sixty-five billion, four hundred twenty-six million, five hundred five thousand, six hundred fifty-five".
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