Base | Representation |
---|---|
bin | 11000110011100110… |
… | …10010101011011011 |
3 | 1021101010202020010012 |
4 | 30121303102223123 |
5 | 204233322400024 |
6 | 10041302112135 |
7 | 651012150341 |
oct | 143163225333 |
9 | 37333666105 |
10 | 13317778139 |
11 | 57145a1916 |
12 | 26b811b64b |
13 | 13431857c3 |
14 | 904a49991 |
15 | 52e2c350e |
hex | 319cd2adb |
13317778139 has 2 divisors, whose sum is σ = 13317778140. Its totient is φ = 13317778138.
The previous prime is 13317778109. The next prime is 13317778181. The reversal of 13317778139 is 93187771331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13317778139 is a prime.
It is a super-3 number, since 3×133177781393 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13317778109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6658889069 + 6658889070.
It is an arithmetic number, because the mean of its divisors is an integer number (6658889070).
Almost surely, 213317778139 is an apocalyptic number.
13317778139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13317778139 is an equidigital number, since it uses as much as digits as its factorization.
13317778139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 666792, while the sum is 50.
The spelling of 13317778139 in words is "thirteen billion, three hundred seventeen million, seven hundred seventy-eight thousand, one hundred thirty-nine".
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