Base | Representation |
---|---|
bin | 11000110011110000… |
… | …11100001010010001 |
3 | 1021101020021210100211 |
4 | 30121320130022101 |
5 | 204234144041242 |
6 | 10041351044121 |
7 | 651026501041 |
oct | 143170341221 |
9 | 37336253324 |
10 | 13319127697 |
11 | 5715333857 |
12 | 26b8670641 |
13 | 1343538b65 |
14 | 904cbb721 |
15 | 52e48d317 |
hex | 319e1c291 |
13319127697 has 2 divisors, whose sum is σ = 13319127698. Its totient is φ = 13319127696.
The previous prime is 13319127659. The next prime is 13319127709. The reversal of 13319127697 is 79672191331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10433396736 + 2885730961 = 102144^2 + 53719^2 .
It is a cyclic number.
It is not a de Polignac number, because 13319127697 - 223 = 13310739089 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13319127697.
It is not a weakly prime, because it can be changed into another prime (13319227697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6659563848 + 6659563849.
It is an arithmetic number, because the mean of its divisors is an integer number (6659563849).
Almost surely, 213319127697 is an apocalyptic number.
It is an amenable number.
13319127697 is a deficient number, since it is larger than the sum of its proper divisors (1).
13319127697 is an equidigital number, since it uses as much as digits as its factorization.
13319127697 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 428652, while the sum is 49.
The spelling of 13319127697 in words is "thirteen billion, three hundred nineteen million, one hundred twenty-seven thousand, six hundred ninety-seven".
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