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1332000113 is a prime number
BaseRepresentation
bin100111101100100…
…1011010101110001
310102211101121122112
41033121023111301
510211443000423
6340101215105
745002546153
oct11731132561
93384347575
101332000113
11623974444
12312101495
13182c60462
14c8c90ad3
157be11a78
hex4f64b571

1332000113 has 2 divisors, whose sum is σ = 1332000114. Its totient is φ = 1332000112.

The previous prime is 1332000101. The next prime is 1332000139. The reversal of 1332000113 is 3110002331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1072693504 + 259306609 = 32752^2 + 16103^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332000113 - 24 = 1332000097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1332000613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666000056 + 666000057.

It is an arithmetic number, because the mean of its divisors is an integer number (666000057).

Almost surely, 21332000113 is an apocalyptic number.

It is an amenable number.

1332000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332000113 is an equidigital number, since it uses as much as digits as its factorization.

1332000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 1332000113 is about 36496.5767298797. The cubic root of 1332000113 is about 1100.2754442451.

Adding to 1332000113 its reverse (3110002331), we get a palindrome (4442002444).

The spelling of 1332000113 in words is "one billion, three hundred thirty-two million, one hundred thirteen", and thus it is an aban number.