Base | Representation |
---|---|
bin | 1100000111010100111010… |
… | …1001010010101010100111 |
3 | 1202011101021121110220221211 |
4 | 3001311032221102222213 |
5 | 3221213341314011403 |
6 | 44155043550252251 |
7 | 2543224224446311 |
oct | 301651651225247 |
9 | 52141247426854 |
10 | 13320013032103 |
11 | 4275a93117248 |
12 | 15b16114b7087 |
13 | 7580c1aa564b |
14 | 3409990827b1 |
15 | 18173dcd806d |
hex | c1d4ea52aa7 |
13320013032103 has 16 divisors (see below), whose sum is σ = 14485038188544. Its totient is φ = 12197391091200.
The previous prime is 13320013032083. The next prime is 13320013032121. The reversal of 13320013032103 is 30123031002331.
13320013032103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13320013032103 - 25 = 13320013032071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13320013032143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31970778 + ... + 32384728.
It is an arithmetic number, because the mean of its divisors is an integer number (905314886784).
Almost surely, 213320013032103 is an apocalyptic number.
13320013032103 is a deficient number, since it is larger than the sum of its proper divisors (1165025156441).
13320013032103 is a wasteful number, since it uses less digits than its factorization.
13320013032103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 465162.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 13320013032103 its reverse (30123031002331), we get a palindrome (43443044034434).
The spelling of 13320013032103 in words is "thirteen trillion, three hundred twenty billion, thirteen million, thirty-two thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •