Base | Representation |
---|---|
bin | 10011011000100001011… |
… | …110001110101011011110 |
3 | 11201100010110200202100211 |
4 | 103120201132032223132 |
5 | 133310414331344314 |
6 | 2455525113243034 |
7 | 165143144244634 |
oct | 23304136165336 |
9 | 4640113622324 |
10 | 1332001434334 |
11 | 4739980a248a |
12 | 19619870347a |
13 | 987b80196bc |
14 | 4867d743354 |
15 | 249ad5e69c4 |
hex | 1362178eade |
1332001434334 has 4 divisors (see below), whose sum is σ = 1998002151504. Its totient is φ = 666000717166.
The previous prime is 1332001434259. The next prime is 1332001434371. The reversal of 1332001434334 is 4334341002331.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×13320014343343 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1332001434296 and 1332001434305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333000358582 + ... + 333000358585.
It is an arithmetic number, because the mean of its divisors is an integer number (499500537876).
Almost surely, 21332001434334 is an apocalyptic number.
1332001434334 is a deficient number, since it is larger than the sum of its proper divisors (666000717170).
1332001434334 is an equidigital number, since it uses as much as digits as its factorization.
1332001434334 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 666000717169.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 1332001434334 its reverse (4334341002331), we get a palindrome (5666342436665).
The spelling of 1332001434334 in words is "one trillion, three hundred thirty-two billion, one million, four hundred thirty-four thousand, three hundred thirty-four".
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