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1332001440051 = 3444000480017
BaseRepresentation
bin10011011000100001011…
…110010000000100110011
311201100010110201001012120
4103120201132100010303
5133310414332040201
62455525113325323
7165143144300412
oct23304136200463
94640113631176
101332001440051
114739980a6807
12196198706843
13987b801c199
144867d745479
15249ad5e8536
hex13621790133

1332001440051 has 4 divisors (see below), whose sum is σ = 1776001920072. Its totient is φ = 888000960032.

The previous prime is 1332001439999. The next prime is 1332001440053. The reversal of 1332001440051 is 1500441002331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1332001440051 - 211 = 1332001438003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1332001440053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222000240006 + ... + 222000240011.

It is an arithmetic number, because the mean of its divisors is an integer number (444000480018).

Almost surely, 21332001440051 is an apocalyptic number.

1332001440051 is a deficient number, since it is larger than the sum of its proper divisors (444000480021).

1332001440051 is an equidigital number, since it uses as much as digits as its factorization.

1332001440051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 444000480020.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 1332001440051 its reverse (1500441002331), we get a palindrome (2832442442382).

The spelling of 1332001440051 in words is "one trillion, three hundred thirty-two billion, one million, four hundred forty thousand, fifty-one".

Divisors: 1 3 444000480017 1332001440051