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13320112112122 = 26660056056061
BaseRepresentation
bin1100000111010101010010…
…0011010000000111111010
31202011101112111220201012011
43001311110203100013322
53221214042200041442
644155101450040134
72543226536560324
oct301652443200772
952141474821164
1013320112112122
11427603403a562
1215b163a71904a
1375810948648a
143409a82b4614
1518174785a117
hexc1d548d01fa

13320112112122 has 4 divisors (see below), whose sum is σ = 19980168168186. Its totient is φ = 6660056056060.

The previous prime is 13320112112119. The next prime is 13320112112159. The reversal of 13320112112122 is 22121121102331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12156930449041 + 1163181663081 = 3486679^2 + 1078509^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13320112112093 and 13320112112102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3330028028029 + ... + 3330028028032.

Almost surely, 213320112112122 is an apocalyptic number.

13320112112122 is a deficient number, since it is larger than the sum of its proper divisors (6660056056064).

13320112112122 is an equidigital number, since it uses as much as digits as its factorization.

13320112112122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6660056056063.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 13320112112122 its reverse (22121121102331), we get a palindrome (35441233214453).

The spelling of 13320112112122 in words is "thirteen trillion, three hundred twenty billion, one hundred twelve million, one hundred twelve thousand, one hundred twenty-two".

Divisors: 1 2 6660056056061 13320112112122