Base | Representation |
---|---|
bin | 10011011000100010001… |
… | …111110110011000111101 |
3 | 11201100011101011121120220 |
4 | 103120202033312120331 |
5 | 133310431144121140 |
6 | 2455530300131553 |
7 | 165143362642200 |
oct | 23304217663075 |
9 | 4640141147526 |
10 | 1332014442045 |
11 | 4739a4477361 |
12 | 1961a0b36bb9 |
13 | 987ba922281 |
14 | 4868136b937 |
15 | 249ae815bd0 |
hex | 136223f663d |
1332014442045 has 48 divisors (see below), whose sum is σ = 2507033954880. Its totient is φ = 602079050496.
The previous prime is 1332014441999. The next prime is 1332014442071. The reversal of 1332014442045 is 5402444102331.
It is not a de Polignac number, because 1332014442045 - 213 = 1332014433853 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1332014441997 and 1332014442015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10115847 + ... + 10246676.
It is an arithmetic number, because the mean of its divisors is an integer number (52229874060).
Almost surely, 21332014442045 is an apocalyptic number.
1332014442045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1332014442045 is a deficient number, since it is larger than the sum of its proper divisors (1175019512835).
1332014442045 is a wasteful number, since it uses less digits than its factorization.
1332014442045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20362634 (or 20362627 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 1332014442045 its reverse (5402444102331), we get a palindrome (6734458544376).
The spelling of 1332014442045 in words is "one trillion, three hundred thirty-two billion, fourteen million, four hundred forty-two thousand, forty-five".
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