Base | Representation |
---|---|
bin | 11110010010010110010000… |
… | …011001000000000111000000 |
3 | 122110122000021100120211112201 |
4 | 132102112100121000013000 |
5 | 114424341143231132000 |
6 | 1151144133223402544 |
7 | 40025354522045326 |
oct | 3622262031000700 |
9 | 573560240524481 |
10 | 133202243224000 |
11 | 394958327a7535 |
12 | 12b335a18b3454 |
13 | 5942bc108aa22 |
14 | 24c7047065d16 |
15 | 105ed6916a96a |
hex | 7925906401c0 |
133202243224000 has 168 divisors, whose sum is σ = 350421231309552. Its totient is φ = 50146725990400.
The previous prime is 133202243223997. The next prime is 133202243224033. The reversal of 133202243224000 is 422342202331.
It is a self number, because there is not a number n which added to its sum of digits gives 133202243224000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26494714 + ... + 31118713.
Almost surely, 2133202243224000 is an apocalyptic number.
133202243224000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133202243224000 is an abundant number, since it is smaller than the sum of its proper divisors (217218988085552).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133202243224000 is an equidigital number, since it uses as much as digits as its factorization.
133202243224000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57613488 (or 57613451 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 133202243224000 its reverse (422342202331), we get a palindrome (133624585426331).
The spelling of 133202243224000 in words is "one hundred thirty-three trillion, two hundred two billion, two hundred forty-three million, two hundred twenty-four thousand".
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