Search a number
-
+
13320234424001 is a prime number
BaseRepresentation
bin1100000111010101101111…
…0101110101011011000001
31202011101212001001210112202
43001311123311311123001
53221214320003032001
644155121535402545
72543232553320611
oct301653365653301
952141761053482
1013320234424001
11427609709025a
1215b1673683455
1375812890c77b
143409ba632a41
1518175346a96b
hexc1d5bd756c1

13320234424001 has 2 divisors, whose sum is σ = 13320234424002. Its totient is φ = 13320234424000.

The previous prime is 13320234423943. The next prime is 13320234424019. The reversal of 13320234424001 is 10042443202331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7079351097025 + 6240883326976 = 2660705^2 + 2498176^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13320234424001 is a prime.

It is a super-2 number, since 2×133202344240012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13320234424031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660117212000 + 6660117212001.

It is an arithmetic number, because the mean of its divisors is an integer number (6660117212001).

Almost surely, 213320234424001 is an apocalyptic number.

It is an amenable number.

13320234424001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320234424001 is an equidigital number, since it uses as much as digits as its factorization.

13320234424001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 13320234424001 its reverse (10042443202331), we get a palindrome (23362677626332).

The spelling of 13320234424001 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-four million, four hundred twenty-four thousand, one".