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133202503130 = 2519369016841
BaseRepresentation
bin111110000001101111…
…1001110010111011010
3110201211010000021000212
41330003133032113122
54140244320100010
6141105315531122
712423611411114
oct1740337162732
9421733007025
10133202503130
1151544382134
12219952b9aa2
13c73a50b7b8
1466389463b4
1536e90a8505
hex1f037ce5da

133202503130 has 16 divisors (see below), whose sum is σ = 241006812264. Its totient is φ = 53004933120.

The previous prime is 133202503003. The next prime is 133202503139. The reversal of 133202503130 is 31305202331.

It can be written as a sum of positive squares in 4 ways, for example, as 61117233961 + 72085269169 = 247219^2 + 268487^2 .

It is a junction number, because it is equal to n+sod(n) for n = 133202503096 and 133202503105.

It is not an unprimeable number, because it can be changed into a prime (133202503139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34506491 + ... + 34510350.

Almost surely, 2133202503130 is an apocalyptic number.

133202503130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133202503130 is a deficient number, since it is larger than the sum of its proper divisors (107804309134).

133202503130 is a wasteful number, since it uses less digits than its factorization.

133202503130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69017041.

The product of its (nonzero) digits is 1620, while the sum is 23.

Adding to 133202503130 its reverse (31305202331), we get a palindrome (164507705461).

The spelling of 133202503130 in words is "one hundred thirty-three billion, two hundred two million, five hundred three thousand, one hundred thirty".

Divisors: 1 2 5 10 193 386 965 1930 69016841 138033682 345084205 690168410 13320250313 26640500626 66601251565 133202503130