Base | Representation |
---|---|
bin | 1100000111010110000001… |
… | …0110010010101011011111 |
3 | 1202011102001022100112222212 |
4 | 3001311200112102223133 |
5 | 3221214443332310221 |
6 | 44155133240231035 |
7 | 2543234462131340 |
oct | 301654026225337 |
9 | 52142038315885 |
10 | 13320310041311 |
11 | 42761258386a9 |
12 | 15b1694a6b47b |
13 | 75813b497040 |
14 | 3409c66b80c7 |
15 | 181759e05b5b |
hex | c1d60592adf |
13320310041311 has 32 divisors (see below), whose sum is σ = 16490094179328. Its totient is φ = 10477681320960.
The previous prime is 13320310041271. The next prime is 13320310041323. The reversal of 13320310041311 is 11314001302331.
13320310041311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13320310041311 - 234 = 13303130172127 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13320310041341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11184335 + ... + 12317871.
It is an arithmetic number, because the mean of its divisors is an integer number (515315443104).
Almost surely, 213320310041311 is an apocalyptic number.
13320310041311 is a deficient number, since it is larger than the sum of its proper divisors (3169784138017).
13320310041311 is a wasteful number, since it uses less digits than its factorization.
13320310041311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1134311.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13320310041311 its reverse (11314001302331), we get a palindrome (24634311343642).
The spelling of 13320310041311 in words is "thirteen trillion, three hundred twenty billion, three hundred ten million, forty-one thousand, three hundred eleven".
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