Base | Representation |
---|---|
bin | 1100000111010110000001… |
… | …1010110000011111000011 |
3 | 1202011102001101120000211122 |
4 | 3001311200122300133003 |
5 | 3221214444132240341 |
6 | 44155133321302455 |
7 | 2543234505105341 |
oct | 301654032603703 |
9 | 52142041500748 |
10 | 13320311211971 |
11 | 4276126468195 |
12 | 15b1695334a2b |
13 | 75813b7b6b3a |
14 | 3409c6900991 |
15 | 18175a08794b |
hex | c1d606b07c3 |
13320311211971 has 2 divisors, whose sum is σ = 13320311211972. Its totient is φ = 13320311211970.
The previous prime is 13320311211959. The next prime is 13320311212063. The reversal of 13320311211971 is 17911211302331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13320311211971 - 238 = 13045433305027 is a prime.
It is not a weakly prime, because it can be changed into another prime (13320311211871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660155605985 + 6660155605986.
It is an arithmetic number, because the mean of its divisors is an integer number (6660155605986).
Almost surely, 213320311211971 is an apocalyptic number.
13320311211971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320311211971 is an equidigital number, since it uses as much as digits as its factorization.
13320311211971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 35.
The spelling of 13320311211971 in words is "thirteen trillion, three hundred twenty billion, three hundred eleven million, two hundred eleven thousand, nine hundred seventy-one".
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