Base | Representation |
---|---|
bin | 1100000111010110000001… |
… | …1010110000100000000001 |
3 | 1202011102001101120000220221 |
4 | 3001311200122300200001 |
5 | 3221214444132241113 |
6 | 44155133321303041 |
7 | 2543234505105460 |
oct | 301654032604001 |
9 | 52142041500827 |
10 | 13320311212033 |
11 | 4276126468241 |
12 | 15b1695334a81 |
13 | 75813b7b6b87 |
14 | 3409c69009d7 |
15 | 18175a08798d |
hex | c1d606b0801 |
13320311212033 has 16 divisors (see below), whose sum is σ = 15787819169280. Its totient is φ = 10995938243136.
The previous prime is 13320311211971. The next prime is 13320311212063. The reversal of 13320311212033 is 33021211302331.
It is a de Polignac number, because none of the positive numbers 2k-13320311212033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13320311211989 and 13320311212007.
It is not an unprimeable number, because it can be changed into a prime (13320311212063) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 82560841 + ... + 82722022.
It is an arithmetic number, because the mean of its divisors is an integer number (986738698080).
Almost surely, 213320311212033 is an apocalyptic number.
It is an amenable number.
13320311212033 is a deficient number, since it is larger than the sum of its proper divisors (2467507957247).
13320311212033 is a wasteful number, since it uses less digits than its factorization.
13320311212033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 165283296.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13320311212033 its reverse (33021211302331), we get a palindrome (46341522514364).
The spelling of 13320311212033 in words is "thirteen trillion, three hundred twenty billion, three hundred eleven million, two hundred twelve thousand, thirty-three".
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