13320440431 has 4 divisors (see below), whose sum is σ = 13645329264. Its totient is φ = 12995551600.

The previous prime is 13320440377. The next prime is 13320440477. The reversal of 13320440431 is 13404402331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13320440431 is a prime.

It is a super-2 number, since 2×13320440431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13320440396 and 13320440405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13320410431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162444355 + ... + 162444436.

It is an arithmetic number, because the mean of its divisors is an integer number (3411332316).

Almost surely, 2^13320440431 is an apocalyptic number.

13320440431 is a deficient number, since it is larger than the sum of its proper divisors (324888833).

13320440431 is an equidigital number, since it uses as much as digits as its factorization.

13320440431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 324888832.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13320440431 its reverse (13404402331), we get a palindrome (26724842762).

The spelling of 13320440431 in words is "thirteen billion, three hundred twenty million, four hundred forty thousand, four hundred thirty-one".