133205413440 has 224 divisors, whose sum is σ = 461641057920. Its totient is φ = 32273612800.

The previous prime is 133205413381. The next prime is 133205413441. The reversal of 133205413440 is 44314502331.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 133205413398 and 133205413407.

It is not an unprimeable number, because it can be changed into a prime (133205413441) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 30209956 + ... + 30214364.

It is an arithmetic number, because the mean of its divisors is an integer number (2060897580).

Almost surely, 2^133205413440 is an apocalyptic number.

133205413440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133205413440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (230820528960).

133205413440 is an abundant number, since it is smaller than the sum of its proper divisors (328435644480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133205413440 is a wasteful number, since it uses less digits than its factorization.

133205413440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7301 (or 7291 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 133205413440 its reverse (44314502331), we get a palindrome (177519915771).

It can be divided in two parts, 133205 and 413440, that added together give a palindrome (546645).

The spelling of 133205413440 in words is "one hundred thirty-three billion, two hundred five million, four hundred thirteen thousand, four hundred forty".