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13321030111423 = 123491107870453
BaseRepresentation
bin1100000111011000101101…
…0001001001000010111111
31202011110220111021220111021
43001312023101021002333
53221222432202031143
644155332522005011
72543261354463166
oct301661321110277
952143814256437
1013321030111423
114276465245a71
1215b1856046767
13758224712728
14340a541983dd
1518179d23eced
hexc1d8b4490bf

13321030111423 has 4 divisors (see below), whose sum is σ = 13321138105368. Its totient is φ = 13320922117480.

The previous prime is 13321030111421. The next prime is 13321030111447. The reversal of 13321030111423 is 32411103012331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13321030111423 - 21 = 13321030111421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13321030111421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53811736 + ... + 54058717.

It is an arithmetic number, because the mean of its divisors is an integer number (3330284526342).

Almost surely, 213321030111423 is an apocalyptic number.

13321030111423 is a deficient number, since it is larger than the sum of its proper divisors (107993945).

13321030111423 is a wasteful number, since it uses less digits than its factorization.

13321030111423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107993944.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13321030111423 its reverse (32411103012331), we get a palindrome (45732133123754).

The spelling of 13321030111423 in words is "thirteen trillion, three hundred twenty-one billion, thirty million, one hundred eleven thousand, four hundred twenty-three".

Divisors: 1 123491 107870453 13321030111423