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1332120220033 is a prime number
BaseRepresentation
bin10011011000101000100…
…011010111000110000001
311201100102202012200201011
4103120220203113012001
5133311140234020113
62455544555240521
7165146116020631
oct23305043270601
94640382180634
101332120220033
11473a49154989
12196210449141
13988068099b5
14486914246c1
15249b8c5c63d
hex136288d7181

1332120220033 has 2 divisors, whose sum is σ = 1332120220034. Its totient is φ = 1332120220032.

The previous prime is 1332120220003. The next prime is 1332120220073. The reversal of 1332120220033 is 3300220212331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 777047539009 + 555072681024 = 881503^2 + 745032^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1332120220033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1332120219986 and 1332120220013.

It is not a weakly prime, because it can be changed into another prime (1332120220003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666060110016 + 666060110017.

It is an arithmetic number, because the mean of its divisors is an integer number (666060110017).

Almost surely, 21332120220033 is an apocalyptic number.

It is an amenable number.

1332120220033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332120220033 is an equidigital number, since it uses as much as digits as its factorization.

1332120220033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 1332120220033 its reverse (3300220212331), we get a palindrome (4632340432364).

The spelling of 1332120220033 in words is "one trillion, three hundred thirty-two billion, one hundred twenty million, two hundred twenty thousand, thirty-three".