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13321203130113 = 34440401043371
BaseRepresentation
bin1100000111011001010110…
…0101001001111100000001
31202011111100112212011111220
43001312111211021330001
53221223311000130423
644155402022225253
72543265555223644
oct301662545117401
952144315764456
1013321203130113
11427654397a51a
1215b18a3b85229
13758251510a58
14340a6d155a5b
151817ad5199e3
hexc1d95949f01

13321203130113 has 4 divisors (see below), whose sum is σ = 17761604173488. Its totient is φ = 8880802086740.

The previous prime is 13321203130061. The next prime is 13321203130121. The reversal of 13321203130113 is 31103130212331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13321203130113 - 240 = 12221691502337 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13321203130013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2220200521683 + ... + 2220200521688.

It is an arithmetic number, because the mean of its divisors is an integer number (4440401043372).

Almost surely, 213321203130113 is an apocalyptic number.

It is an amenable number.

13321203130113 is a deficient number, since it is larger than the sum of its proper divisors (4440401043375).

13321203130113 is an equidigital number, since it uses as much as digits as its factorization.

13321203130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4440401043374.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 13321203130113 its reverse (31103130212331), we get a palindrome (44424333342444).

The spelling of 13321203130113 in words is "thirteen trillion, three hundred twenty-one billion, two hundred three million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 4440401043371 13321203130113