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13321214221241 is a prime number
BaseRepresentation
bin1100000111011001011000…
…1111011101101110111001
31202011111101022201122200102
43001312112033131232321
53221223321320034431
644155403100045145
72543266051416413
oct301662617355671
952144338648612
1013321214221241
11427654a165443
1215b18a78337b5
137582538c5154
14340a708019b3
151817ae4aadcb
hexc1d963ddbb9

13321214221241 has 2 divisors, whose sum is σ = 13321214221242. Its totient is φ = 13321214221240.

The previous prime is 13321214221169. The next prime is 13321214221279. The reversal of 13321214221241 is 14212241212331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13178497248400 + 142716972841 = 3630220^2 + 377779^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13321214221241 is a prime.

It is not a weakly prime, because it can be changed into another prime (13321214221541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660607110620 + 6660607110621.

It is an arithmetic number, because the mean of its divisors is an integer number (6660607110621).

Almost surely, 213321214221241 is an apocalyptic number.

It is an amenable number.

13321214221241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321214221241 is an equidigital number, since it uses as much as digits as its factorization.

13321214221241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4608, while the sum is 29.

Adding to 13321214221241 its reverse (14212241212331), we get a palindrome (27533455433572).

The spelling of 13321214221241 in words is "thirteen trillion, three hundred twenty-one billion, two hundred fourteen million, two hundred twenty-one thousand, two hundred forty-one".