Base | Representation |
---|---|
bin | 1100000111011001011001… |
… | …0000010001000001101101 |
3 | 1202011111101100010022212220 |
4 | 3001312112100101001231 |
5 | 3221223321343300331 |
6 | 44155403104345553 |
7 | 2543266053253065 |
oct | 301662620210155 |
9 | 52144340108786 |
10 | 13321214431341 |
11 | 427654a299283 |
12 | 15b18a79152b9 |
13 | 75825396997b |
14 | 340a708583a5 |
15 | 1817ae4ed296 |
hex | c1d9641106d |
13321214431341 has 4 divisors (see below), whose sum is σ = 17761619241792. Its totient is φ = 8880809620892.
The previous prime is 13321214431333. The next prime is 13321214431387. The reversal of 13321214431341 is 14313441212331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13321214431341 - 23 = 13321214431333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13321214431321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2220202405221 + ... + 2220202405226.
It is an arithmetic number, because the mean of its divisors is an integer number (4440404810448).
Almost surely, 213321214431341 is an apocalyptic number.
It is an amenable number.
13321214431341 is a deficient number, since it is larger than the sum of its proper divisors (4440404810451).
13321214431341 is an equidigital number, since it uses as much as digits as its factorization.
13321214431341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4440404810450.
The product of its digits is 20736, while the sum is 33.
Adding to 13321214431341 its reverse (14313441212331), we get a palindrome (27634655643672).
The spelling of 13321214431341 in words is "thirteen trillion, three hundred twenty-one billion, two hundred fourteen million, four hundred thirty-one thousand, three hundred forty-one".
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