Base | Representation |
---|---|
bin | 10011011000101000110… |
… | …011011000100001001011 |
3 | 11201100110001010002012211 |
4 | 103120220303120201023 |
5 | 133311142322421141 |
6 | 2455545225245551 |
7 | 165146166513136 |
oct | 23305063304113 |
9 | 4640401102184 |
10 | 1332124420171 |
11 | 473a50563576 |
12 | 1962119338b7 |
13 | 9880764a69c |
14 | 48691bd921d |
15 | 249b92dbd81 |
hex | 13628cd884b |
1332124420171 has 2 divisors, whose sum is σ = 1332124420172. Its totient is φ = 1332124420170.
The previous prime is 1332124420079. The next prime is 1332124420303. The reversal of 1332124420171 is 1710244212331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1332124420171 - 223 = 1332116031563 is a prime.
It is not a weakly prime, because it can be changed into another prime (1332124420871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666062210085 + 666062210086.
It is an arithmetic number, because the mean of its divisors is an integer number (666062210086).
Almost surely, 21332124420171 is an apocalyptic number.
1332124420171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332124420171 is an equidigital number, since it uses as much as digits as its factorization.
1332124420171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
The spelling of 1332124420171 in words is "one trillion, three hundred thirty-two billion, one hundred twenty-four million, four hundred twenty thousand, one hundred seventy-one".
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