Base | Representation |
---|---|
bin | 10011011000101000110… |
… | …011011000100001100111 |
3 | 11201100110001010002020212 |
4 | 103120220303120201213 |
5 | 133311142322421244 |
6 | 2455545225250035 |
7 | 165146166513206 |
oct | 23305063304147 |
9 | 4640401102225 |
10 | 1332124420199 |
11 | 473a505635a1 |
12 | 19621193391b |
13 | 9880764a6c1 |
14 | 48691bd923d |
15 | 249b92dbd9e |
hex | 13628cd8867 |
1332124420199 has 4 divisors (see below), whose sum is σ = 1332220125840. Its totient is φ = 1332028714560.
The previous prime is 1332124420171. The next prime is 1332124420303. The reversal of 1332124420199 is 9910244212331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1332124420199 - 228 = 1331855984743 is a prime.
It is a super-3 number, since 3×13321244201993 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1332124420499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47831939 + ... + 47859780.
It is an arithmetic number, because the mean of its divisors is an integer number (333055031460).
Almost surely, 21332124420199 is an apocalyptic number.
1332124420199 is a deficient number, since it is larger than the sum of its proper divisors (95705641).
1332124420199 is an equidigital number, since it uses as much as digits as its factorization.
1332124420199 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95705640.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 1332124420199 in words is "one trillion, three hundred thirty-two billion, one hundred twenty-four million, four hundred twenty thousand, one hundred ninety-nine".
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