Base | Representation |
---|---|
bin | 11110010010100000010111… |
… | …100000010111001010101011 |
3 | 122110200001021222112211010111 |
4 | 132102200113200113022223 |
5 | 114430030412100342303 |
6 | 1151153130414155151 |
7 | 40026220542163141 |
oct | 3622402740271253 |
9 | 573601258484114 |
10 | 133213100012203 |
11 | 3949a3a410a172 |
12 | 12b357117b2ab7 |
13 | 5943c31422163 |
14 | 24c7796cd7591 |
15 | 10602a236bb6d |
hex | 7928178172ab |
133213100012203 has 2 divisors, whose sum is σ = 133213100012204. Its totient is φ = 133213100012202.
The previous prime is 133213100012123. The next prime is 133213100012207. The reversal of 133213100012203 is 302210001312331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133213100012203 - 217 = 133213099881131 is a prime.
It is a super-2 number, since 2×1332131000122032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133213100012207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66606550006101 + 66606550006102.
It is an arithmetic number, because the mean of its divisors is an integer number (66606550006102).
Almost surely, 2133213100012203 is an apocalyptic number.
133213100012203 is a deficient number, since it is larger than the sum of its proper divisors (1).
133213100012203 is an equidigital number, since it uses as much as digits as its factorization.
133213100012203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 133213100012203 its reverse (302210001312331), we get a palindrome (435423101324534).
The spelling of 133213100012203 in words is "one hundred thirty-three trillion, two hundred thirteen billion, one hundred million, twelve thousand, two hundred three".
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