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13321320036049 is a prime number
BaseRepresentation
bin1100000111011001110010…
…0011000111011011010001
31202011111122200211121022101
43001312130203013123101
53221224030412123144
644155421400040401
72543301505010404
oct301663443073321
952144580747271
1013321320036049
1142765a39686a3
1215b1917163101
1375826c7c356c
14340a808a7d3b
151817b890d6d4
hexc1d9c8c76d1

13321320036049 has 2 divisors, whose sum is σ = 13321320036050. Its totient is φ = 13321320036048.

The previous prime is 13321320036001. The next prime is 13321320036061. The reversal of 13321320036049 is 94063002312331.

13321320036049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11856094519824 + 1465225516225 = 3443268^2 + 1210465^2 .

It is a cyclic number.

It is not a de Polignac number, because 13321320036049 - 27 = 13321320035921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13321320035999 and 13321320036017.

It is not a weakly prime, because it can be changed into another prime (13321320036449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660660018024 + 6660660018025.

It is an arithmetic number, because the mean of its divisors is an integer number (6660660018025).

Almost surely, 213321320036049 is an apocalyptic number.

It is an amenable number.

13321320036049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321320036049 is an equidigital number, since it uses as much as digits as its factorization.

13321320036049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 37.

The spelling of 13321320036049 in words is "thirteen trillion, three hundred twenty-one billion, three hundred twenty million, thirty-six thousand, forty-nine".