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133213334554300 = 2252721113190114649
BaseRepresentation
bin11110010010100000100101…
…011111000100011010111100
3122110200001220022212210101211
4132102200211133010122330
5114430031402121214200
61151153205553214204
740026226420564300
oct3622404537043274
9573601808783354
10133213334554300
113949a504545110
1212b35778261364
135943c6abb1970
1424c77ba10bd00
1510602b7c4aaba
hex7928257c46bc

133213334554300 has 216 divisors, whose sum is σ = 395056721782800. Its totient is φ = 38327113036800.

The previous prime is 133213334554259. The next prime is 133213334554327. The reversal of 133213334554300 is 3455433312331.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 94356625 + ... + 95758024.

It is an arithmetic number, because the mean of its divisors is an integer number (1828966304550).

Almost surely, 2133213334554300 is an apocalyptic number.

133213334554300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133213334554300 is an abundant number, since it is smaller than the sum of its proper divisors (261843387228500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133213334554300 is a wasteful number, since it uses less digits than its factorization.

133213334554300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190114701 (or 190114687 counting only the distinct ones).

The product of its (nonzero) digits is 583200, while the sum is 40.

Adding to 133213334554300 its reverse (3455433312331), we get a palindrome (136668767866631).

The spelling of 133213334554300 in words is "one hundred thirty-three trillion, two hundred thirteen billion, three hundred thirty-four million, five hundred fifty-four thousand, three hundred".