Base | Representation |
---|---|
bin | 11110010010100110110100… |
… | …000001110101011110111011 |
3 | 122110200201011022121102201102 |
4 | 132102212310001311132323 |
5 | 114430134100334000443 |
6 | 1151200233251042015 |
7 | 40026554211462401 |
oct | 3622466401653673 |
9 | 573621138542642 |
10 | 133220021000123 |
11 | 394a23258a78a2 |
12 | 12b36b235a030b |
13 | 5944795252595 |
14 | 24c7c52167471 |
15 | 1060559c79cb8 |
hex | 7929b40757bb |
133220021000123 has 2 divisors, whose sum is σ = 133220021000124. Its totient is φ = 133220021000122.
The previous prime is 133220021000071. The next prime is 133220021000177. The reversal of 133220021000123 is 321000120022331.
It is a weak prime.
It is an emirp because it is prime and its reverse (321000120022331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133220021000123 - 28 = 133220020999867 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133220021000095 and 133220021000104.
It is not a weakly prime, because it can be changed into another prime (133220021000623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66610010500061 + 66610010500062.
It is an arithmetic number, because the mean of its divisors is an integer number (66610010500062).
Almost surely, 2133220021000123 is an apocalyptic number.
133220021000123 is a deficient number, since it is larger than the sum of its proper divisors (1).
133220021000123 is an equidigital number, since it uses as much as digits as its factorization.
133220021000123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 133220021000123 its reverse (321000120022331), we get a palindrome (454220141022454).
The spelling of 133220021000123 in words is "one hundred thirty-three trillion, two hundred twenty billion, twenty-one million, one hundred twenty-three", and thus it is an aban number.
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