Base | Representation |
---|---|
bin | 1100000111011100010111… |
… | …1011111101001001011111 |
3 | 1202011120110002102121222022 |
4 | 3001313011323331021133 |
5 | 3221231441142212112 |
6 | 44200014323010355 |
7 | 2543324636063240 |
oct | 301670573751137 |
9 | 52146402377868 |
10 | 13322014413407 |
11 | 427691a917687 |
12 | 15b1a8b8099bb |
13 | 75835061463b |
14 | 340b08bbacc7 |
15 | 18180986ed72 |
hex | c1dc5efd25f |
13322014413407 has 16 divisors (see below), whose sum is σ = 16361365259520. Its totient is φ = 10586765743488.
The previous prime is 13322014413397. The next prime is 13322014413443. The reversal of 13322014413407 is 70431441022331.
It is a cyclic number.
It is not a de Polignac number, because 13322014413407 - 212 = 13322014409311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13322014413467) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 835437557 + ... + 835453502.
It is an arithmetic number, because the mean of its divisors is an integer number (1022585328720).
Almost surely, 213322014413407 is an apocalyptic number.
13322014413407 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
13322014413407 is a deficient number, since it is larger than the sum of its proper divisors (3039350846113).
13322014413407 is a wasteful number, since it uses less digits than its factorization.
13322014413407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1670891150.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 13322014413407 its reverse (70431441022331), we get a palindrome (83753455435738).
The spelling of 13322014413407 in words is "thirteen trillion, three hundred twenty-two billion, fourteen million, four hundred thirteen thousand, four hundred seven".
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