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13322014413397 is a prime number
BaseRepresentation
bin1100000111011100010111…
…1011111101001001010101
31202011120110002102121221221
43001313011323331021111
53221231441142212042
644200014323010341
72543324636063224
oct301670573751125
952146402377857
1013322014413397
11427691a917678
1215b1a8b8099b1
13758350614631
14340b08bbacbb
1518180986ed67
hexc1dc5efd255

13322014413397 has 2 divisors, whose sum is σ = 13322014413398. Its totient is φ = 13322014413396.

The previous prime is 13322014413313. The next prime is 13322014413443. The reversal of 13322014413397 is 79331441022331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13055170881636 + 266843531761 = 3613194^2 + 516569^2 .

It is a cyclic number.

It is not a de Polignac number, because 13322014413397 - 27 = 13322014413269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13322014413797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661007206698 + 6661007206699.

It is an arithmetic number, because the mean of its divisors is an integer number (6661007206699).

Almost surely, 213322014413397 is an apocalyptic number.

It is an amenable number.

13322014413397 is a deficient number, since it is larger than the sum of its proper divisors (1).

13322014413397 is an equidigital number, since it uses as much as digits as its factorization.

13322014413397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 43.

The spelling of 13322014413397 in words is "thirteen trillion, three hundred twenty-two billion, fourteen million, four hundred thirteen thousand, three hundred ninety-seven".