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133220332011021 = 380595510209373
BaseRepresentation
bin11110010010100111000110…
…100100001111111000001101
3122110200201221222211102110120
4132102213012210033320031
5114430140214443323041
61151200324201055153
740026565006151613
oct3622470644177015
9573621858742416
10133220332011021
11394a24754119a2
1212b36bab7874b9
1359448148070b8
1424c7c815a56b3
151060577211366
hex7929c690fe0d

133220332011021 has 8 divisors (see below), whose sum is σ = 177649150217760. Its totient is φ = 88802534239152.

The previous prime is 133220332010993. The next prime is 133220332011043. The reversal of 133220332011021 is 120110233022331.

133220332011021 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133220332011021 - 219 = 133220331486733 is a prime.

It is a super-2 number, since 2×1332203320110212 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133220332010982 and 133220332011000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133220332012021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2755080510 + ... + 2755128863.

It is an arithmetic number, because the mean of its divisors is an integer number (22206143777220).

Almost surely, 2133220332011021 is an apocalyptic number.

It is an amenable number.

133220332011021 is a deficient number, since it is larger than the sum of its proper divisors (44428818206739).

133220332011021 is an equidigital number, since it uses as much as digits as its factorization.

133220332011021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5510217435.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 133220332011021 its reverse (120110233022331), we get a palindrome (253330565033352).

The spelling of 133220332011021 in words is "one hundred thirty-three trillion, two hundred twenty billion, three hundred thirty-two million, eleven thousand, twenty-one".

Divisors: 1 3 8059 24177 5510209373 16530628119 44406777337007 133220332011021