Base | Representation |
---|---|
bin | 1100000111011100110001… |
… | …0011010110110110100111 |
3 | 1202011120201112101112010221 |
4 | 3001313030103112312213 |
5 | 3221232201012230203 |
6 | 44200033100025211 |
7 | 2543330403620332 |
oct | 301671423266647 |
9 | 52146645345127 |
10 | 13322121211303 |
11 | 4276975131503 |
12 | 15b1abb532207 |
13 | 758369798368 |
14 | 340b1905b619 |
15 | 181813e18abd |
hex | c1dcc4d6da7 |
13322121211303 has 4 divisors (see below), whose sum is σ = 13901343872688. Its totient is φ = 12742898549920.
The previous prime is 13322121211277. The next prime is 13322121211387. The reversal of 13322121211303 is 30311212122331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13322121211303 - 233 = 13313531276711 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13322124211303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289611330658 + ... + 289611330703.
It is an arithmetic number, because the mean of its divisors is an integer number (3475335968172).
Almost surely, 213322121211303 is an apocalyptic number.
13322121211303 is a deficient number, since it is larger than the sum of its proper divisors (579222661385).
13322121211303 is an equidigital number, since it uses as much as digits as its factorization.
13322121211303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 579222661384.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13322121211303 its reverse (30311212122331), we get a palindrome (43633333333634).
The spelling of 13322121211303 in words is "thirteen trillion, three hundred twenty-two billion, one hundred twenty-one million, two hundred eleven thousand, three hundred three".
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