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1332233952017 is a prime number
BaseRepresentation
bin10011011000101111010…
…101001101101100010001
311201100201200012212122212
4103120233111031230101
5133311403342431032
62500004141041505
7165151666515023
oct23305725155421
94640650185585
101332233952017
11473aa7375461
12196242556295
139882424a927
14486a258c013
15249c3c25bb2
hex1362f54db11

1332233952017 has 2 divisors, whose sum is σ = 1332233952018. Its totient is φ = 1332233952016.

The previous prime is 1332233951989. The next prime is 1332233952031. The reversal of 1332233952017 is 7102593322331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1022573978176 + 309659973841 = 1011224^2 + 556471^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332233952017 - 216 = 1332233886481 is a prime.

It is not a weakly prime, because it can be changed into another prime (1332233952047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666116976008 + 666116976009.

It is an arithmetic number, because the mean of its divisors is an integer number (666116976009).

Almost surely, 21332233952017 is an apocalyptic number.

It is an amenable number.

1332233952017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332233952017 is an equidigital number, since it uses as much as digits as its factorization.

1332233952017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 41.

The spelling of 1332233952017 in words is "one trillion, three hundred thirty-two billion, two hundred thirty-three million, nine hundred fifty-two thousand, seventeen".