Base | Representation |
---|---|
bin | 11110010010101010101000… |
… | …001011001000010111001101 |
3 | 122110201002201210002201111012 |
4 | 132102222220023020113031 |
5 | 114430220442432434303 |
6 | 1151202151532135005 |
7 | 40030060546532663 |
oct | 3622525013102715 |
9 | 573632653081435 |
10 | 133224117077453 |
11 | 394a4037a43376 |
12 | 12b37887307465 |
13 | 5944c98a4318c |
14 | 24c812016ac33 |
15 | 10606e967c5d8 |
hex | 792aa82c85cd |
133224117077453 has 16 divisors (see below), whose sum is σ = 145275994423296. Its totient is φ = 121819974405360.
The previous prime is 133224117077449. The next prime is 133224117077477. The reversal of 133224117077453 is 354770711422331.
It is not a de Polignac number, because 133224117077453 - 22 = 133224117077449 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133224117077423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1432994813 + ... + 1433087778.
It is an arithmetic number, because the mean of its divisors is an integer number (9079749651456).
Almost surely, 2133224117077453 is an apocalyptic number.
It is an amenable number.
133224117077453 is a deficient number, since it is larger than the sum of its proper divisors (12051877345843).
133224117077453 is a wasteful number, since it uses less digits than its factorization.
133224117077453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2866082704.
The product of its (nonzero) digits is 2963520, while the sum is 50.
Adding to 133224117077453 its reverse (354770711422331), we get a palindrome (487994828499784).
The spelling of 133224117077453 in words is "one hundred thirty-three trillion, two hundred twenty-four billion, one hundred seventeen million, seventy-seven thousand, four hundred fifty-three".
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