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133224240257 is a prime number
BaseRepresentation
bin111110000010011001…
…0001001010010000001
3110201212121220121202122
41330010302021102001
54140320401142012
6141111413454025
712424264233503
oct1740462112201
9421777817678
10133224240257
11515556795a9
12219a0641315
13c741b7c7c4
14663b7a3d73
1536eae4de72
hex1f04c89481

133224240257 has 2 divisors, whose sum is σ = 133224240258. Its totient is φ = 133224240256.

The previous prime is 133224240209. The next prime is 133224240277. The reversal of 133224240257 is 752042422331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67101203521 + 66123036736 = 259039^2 + 257144^2 .

It is an emirp because it is prime and its reverse (752042422331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133224240257 - 210 = 133224239233 is a prime.

It is not a weakly prime, because it can be changed into another prime (133224240277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66612120128 + 66612120129.

It is an arithmetic number, because the mean of its divisors is an integer number (66612120129).

Almost surely, 2133224240257 is an apocalyptic number.

It is an amenable number.

133224240257 is a deficient number, since it is larger than the sum of its proper divisors (1).

133224240257 is an equidigital number, since it uses as much as digits as its factorization.

133224240257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80640, while the sum is 35.

Adding to 133224240257 its reverse (752042422331), we get a palindrome (885266662588).

The spelling of 133224240257 in words is "one hundred thirty-three billion, two hundred twenty-four million, two hundred forty thousand, two hundred fifty-seven".