Search a number
-
+
133231055719673 is a prime number
BaseRepresentation
bin11110010010110001000101…
…101111111100110011111001
3122110201202122100101021020002
4132102301011233330303321
5114430324200231012143
61151205300235242345
740030424522161412
oct3622610557746371
9573652570337202
10133231055719673
11394a6a78699a2a
1212b390a2ba93b5
135945833415132
1424c85bb8b4809
1510609a38c65b8
hex792c45bfccf9

133231055719673 has 2 divisors, whose sum is σ = 133231055719674. Its totient is φ = 133231055719672.

The previous prime is 133231055719613. The next prime is 133231055719681. The reversal of 133231055719673 is 376917550132331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92916721406224 + 40314334313449 = 9639332^2 + 6349357^2 .

It is a cyclic number.

It is not a de Polignac number, because 133231055719673 - 214 = 133231055703289 is a prime.

It is a super-2 number, since 2×1332310557196732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133231055719613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66615527859836 + 66615527859837.

It is an arithmetic number, because the mean of its divisors is an integer number (66615527859837).

Almost surely, 2133231055719673 is an apocalyptic number.

It is an amenable number.

133231055719673 is a deficient number, since it is larger than the sum of its proper divisors (1).

133231055719673 is an equidigital number, since it uses as much as digits as its factorization.

133231055719673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10716300, while the sum is 56.

The spelling of 133231055719673 in words is "one hundred thirty-three trillion, two hundred thirty-one billion, fifty-five million, seven hundred nineteen thousand, six hundred seventy-three".